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ra1l [238]
3 years ago
6

6 freshmen, 9 sophomores, 8 juniors, and 10 seniors are eligible to be on a committee. If a committee of 14 students is chosen a

t random, what is the probability that it is made up of 2 freshmen, 3 sophomores, 4 juniors, and 5 seniors?
Round your answer to 6 decimal places as needed.

Mathematics
1 answer:
denpristay [2]3 years ago
8 0
<h3>Answer: 0.027145</h3>

=========================================

Work Shown:

You will be using the nCr combination formula here. Refer to the attached image below (figures 1 through 5).

We have a pool of n = 6 freshmen and we're selecting r = 2 individuals from this pool, so there are nCr = 6C2 = 15 ways to pick the two freshmen (see figure 1).

There are 84 ways to pick the sophomores since 9 C 3 = 84 (see figure 2)

Refer to figure 3 to see how 8 C 4 = 70. So there are 70 ways to pick the juniors.

Refer to figure 4 to see how 10 C 5 = 252. There are 252 ways to pick the seniors.

Finally, refer to figure 5 to see how 33 C 14 = 818,809,200. This is the number of ways to pick 14 students from a pool of 33 (add up all the students).

--------------

Multiply out the results of figures 1 through 4 to get:

15*84*70*252 = 22,226,400

This represents the number of ways to select all the students as mentioned in the instructions.

Then divide this over the result of figure 5

(22,226,400)/(818,809,200) = 0.02714478537858

This rounds to 0.027145 when rounding to 6 decimal places.

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Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A,              3·p²

0,               0

1,                1

2,               12

3,               27

4,               48

5,               75

6,               108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

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