Answer:(6x^2 - 3x^3)/2sqrt(x-1)
Step-by-step explanation: please see attachment for explanation
C.
Domain: x>-1
Range y>-1
d.
Domain: -∞<x<∞
Range: -∞<y<∞
Perimeter=4*side so
side=p/4 and we are told p=16x+32y so
s=(16x+32y)/4
s=4x+8y
s=4(x+2y)
Replace the CIRCLES by A and the SQUARES by B:
1) A + B = 14 And
2) A - B = 2
Add 1) + 2)
A+B =14
A-B = 2
------ ----
2A+0 = 16 then A = 16/2 = 8. If A = 8, then B = 6
So the CIRCLE = 8 and the SQUARE = 6
3x+3=9
x=2
that way the answer is 9