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3 years ago

3 √ 7 + √ 7 can someone elaborate this for me

Mathematics

2 answers:

makkiz [27]3 years ago

4 0

Answer:

The answer is 4 \sqrt{7}.

Step-by-step explanation:

The formula is a\sqrt{x} + b\sqrt{x} = (a+b)\sqrt{x}, but if you don't understand it, here's an easier way to think about it.

You can think of \sqrt{7} as x (or any other variable). Now, the equation is 3x + x. If you've ever done algebra, (you probably have if square roots popped up on your homework) you know that this equals to 4x. Now, replace the x with \sqrt{7}, because we already decided that those two were equal. Therefore, the answer is

4 \sqrt{7}.

Iteru [2.4K]3 years ago

3 0

Answer:

9.3

Step-by-step explanation:

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$\boxed{x = 7}$

Move 1 to the left side of the equation by subtracting it from both sides.

$\sqrt{2x -5 - 2 - 1 = 0 }$

Subtract 1 from -2.

$\sqrt{2x -5 - 3 = 0 }$

Add 3 to both sides of the equation.

$\sqrt{2x - 5 = 3}$

To remove the radical on the left side of the equation, square both sides of the equation.

$\sqrt{2x - 5^3 = 3^2}$

Simplify each side of the equation.

Multiply the exponents in $(( 2x - 5) ^\frac{1}{2})^2$ .

Apply the power rule and multiply exponents, $(a^m)^n = a^mn$

$(2x -5)^\frac{1}{2}.2 = 3^2$

Cancel the common factor of 2.

$(2x - 5)^1 = 3^2$

Simplify.

$2x - 5 = 3^2$

Raise 3 to the power of 2.

$2x - 5 = 9$

Solve for x

Move all terms not containing x to the right side of the equation.

Add 5 to both sides of the equation.

$2x = 9 + 5$

Add 9 and 5.

$2x = 14$

Divide each term by 2 and simplify.

Divide each term in 2x = 14 by 2.

$\frac{2x}{2} = \frac{14}{2}$

Cancel the common factor of 2.

$x = \frac{14}{2}$

Divide 14 by 2.

$x = 7$

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Hope this helped you.

Could you maybe give brainliest..?

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