Can anyone answer this question??

Mathematics

1 answer:

RoseWind [281]2 years ago

4 0

Answer:

i) 75.8

ii) 997,002

Step-by-step explanation:

Each of these expressions can be rewritten to make evaluation a little easier.

The difference of squares can be factored.

a^2 -b^2 = (a -b)(a +b)

8.79^2 -1.21^2 = (8.79 -1.21)(8.79 +1.21) = (7.58)(10) = 75.8

The values are near 1000, so can be expressed as differences from that number.

(999)(998) = (1000 -1)(1000 -2) = 1000^2 -3(1000) +2) = 997,002

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Davon is picking out some movies to rent, and he has narrowed down his selections to 4 children's movies, 3 documentaries, 6 com

earnstyle [38]

Answer:

220

Step-by-step explanation:

There are 6 comedies and 12 non-comedies. He wants all 6 of the comedies, and 3 of the non-comedies.

The number of ways he can choose 6 comedies from 6 is ₆C₆ = 1.

The number of ways he can choose 3 non-comedies from 12 is ₁₂C₃ = 220.

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2 years ago

9) Which equation represents the line that passes through the point (3,4) and is parallel to the x-axis?

kobusy [5.1K]

Since the line is parallell to the x-axis we know the slope is zero: $m=0$

Using the point-slope formula we can substitute know values:
$y=mx+b$
$4=0(3)+b$
$b=4$
$y=0x+4$
$y=4$

You could also jsut do it by inspection: since it passes through (3,4) and is horizontal it must cross at (0,4) i.e. all y=4.

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3 years ago

A ship is sailing due north. At a certain point the bearing of a lighthouse is N 42.8∘E and the distance is 10.5. After a while,

bija089 [108]

Answer:

How far did the ship travel between the two observations of the lighthouse = 9.29

Step-by-step explanation:

the first step to answer this question is drawing the illustration as the attachment.

P is the ship, R is the light house and Q is the bearing.

PR is the distance between the ship and the light house, PR = 10.5

∠P = 42.8°, ∠Q = 59.7°

Thus, ∠R = 180° - ∠P - ∠Q