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gregori [183]
3 years ago
14

Rabbit fur color is controlled by a single gene with two alleles displaying complete dominance. A wild rabbit population inhabit

ing a forest is observed, and the frequency of each fur color was calculated as a percentage of the total population.
Year 0

Rabbit Fur Color

Percent of Individuals

Brown

73%

White

24%


Ten years later the same population is observed.

Year 0

Rabbit Fur Color

Percent of Individuals

Brown

93%

White

7%


Discuss two factors that may have contributed to the shift in genotypic frequency. (5 points)
Biology
1 answer:
sukhopar [10]3 years ago
8 0

Answer:

One factor would be adaptation to the environment. The brown rabbit blends in and doesn't stand out to predators

The second factor because the white rabbits do stand out to predators they are then killed and can not reproduce.

Explanation:

You might be interested in
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
Please help me in science!
lidiya [134]
D. As salt water in the oceans.
7 0
3 years ago
I need help!!!!!!!!!!!!!!!!
ale4655 [162]

<em>Answer:</em>

C. Many, many years of deposition

<em>Explanation:</em>

The layers of the rocks in one region of the parks are smooth and distinct, which are evidence of many, many years of deposition.

The layers on the rocks are because of different deposition of sediments. Different sediments deposited over the rocks through the wind, water, and ice over the ages.

Have a beautiful day.

8 0
3 years ago
Read 2 more answers
1) List 10 ways that energy is used in your home or outside of your home.
tangare [24]

Answer:

There are many ways to save energy at home some are as following:-

1)Use Led Bulbs rather than Tubelight

2)Using Heater or Air Conditioner uses a lot of energy so we should reduce there usage

3)If possible, install a programmable thermostat to automatically adjust your home's temperature settings when you're away or sleeping.

4)Use a bucket of water rather than taking a shower

5)During Winter season use suns heat to heat up your body rather than using heater at day time

6)Save water by scraping dishes instead of rinsing them before loading in the dishwasher

7)Close the tap when not in use

8)While brushing tour teeth, use utensils to clean your mouth rather than using a tap

9)The water you use to mop the floor can we used to water the plant or even clean your car

10)Dont use dryer to dry your cloth rather put it in under sun

Explanation:

PLEASE MARK ME AS BRAINLIEST

3 0
3 years ago
Neurons have special proteins in the cell membranes that control the flow of charged ions. Are these proteins most likely produc
Zielflug [23.3K]

The ribosomes on the rough endoplasmic reticulum (RER) most likely produces neuronal special proteins.

Explanation:

Conduction of electrical impulses by action potentials of neurons takes place through controlled flow of charged ions through neuronal membranes. This ion transfer is controlled by specialized neuronal channel proteins which are present in the neuronal cell membrane.  

These channel proteins allow for hydrophillic passage of ions and water molecules across the neuronal membranes.  

Ribosomes that are attached to the RER are involved in protein synthesis. They carry the code for proteins carried by the mRNA and translate into respective protein.

The RER along with some free ribosomes cluster together as Nissl bodies and are mainly involved in neuronal specialized proteins.

3 0
3 years ago
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