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Marrrta [24]
3 years ago
7

Someone answer. Will give brainlest

Mathematics
1 answer:
Leto [7]3 years ago
5 0

Area inside the semi-circle and outside the triangle is  (91.125π - 120) in²

Solution:

Base of the triangle = 10 in

Height of the triangle = 24 in

Area of the triangle = \frac{1}{2} bh

                                $=\frac{1}{2} \times 10\times24

Area of the triangle = 120 in²

Using Pythagoras theorem,

\text{Hypotenuse}^2=\text{base}^2+\text{height}^2

\text{Hypotenuse}^2=10^2+24^2

\text{Hypotenuse}^2=100+576

\text{Hypotenuse}^2=676

Taking square root on both sides, we get

Hypotenuse = 23 inch = diameter

Radius = 23 ÷ 2 = 11.5 in

Area of the semi-circle = \frac{1}{2}\pi r^2

                                      $=\frac{1}{2} \pi \times (13.5)^2

Area of the semi-circle = 91.125π in²

Area of the shaded portion = (91.125π - 120)  in²

Area inside the semi-circle and outside the triangle is  (91.125π - 120)  in².

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4 0
3 years ago
160 bananas; 20% decrease
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then you multiply .20 by 160 and get 32
then subtract:
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Hope this helped!! :D
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In the number 3,287,854 how many times greater is the value of the 8 in the ten thousands place compared to the value of the 8 i
olga55 [171]

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6 0
3 years ago
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Natali [406]

Answer:

\sqrt{514} cm, 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

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But if 17cm is the longest side then:

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Hope this helps!

4 0
3 years ago
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