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jekas [21]
2 years ago
12

1/5 of the shoes in a factory are green. If you pick a shoe, replace it, pick another shoe and replace it, and pick a third shoe

, what is the probability that none of the shoes are green?
Mathematics
1 answer:
Ne4ueva [31]2 years ago
7 0

Answer:

The probability that none of the three shoes selected are green = 64/125

Step-by-step explanation:

If we have 1/5 of shoes being green, then the number of non-green shoes = 1-1/5 = 4/5

Now, this is a probability with replacement.

probability of the first shoe since it’s not green = 4/5

probability of second shoes since it’s not green = 4/5

probability of third shoe since it’s not green = 4/5

Now, the probability that none of the shoes are green = 4/5 * 4/5 * 4/5 = 64/125

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givi [52]

Answer:

  (x, y) = (77/240, -3/10)

Step-by-step explanation:

It is convenient to write the equations in standard form.

Multiplying the first equation by 21 gives ...

  21y = 24x -14

Multiplying the second equation by 8 gives ...

  24x +9y = 5

Then the system of equations in standard form is ...

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  • 24x +9y = 5

Subtracting the first from the second, we get ...

  (24x +9y) -(24x -21y) = (5) -(14)

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Substituting this into the second equation, we have ...

  24x +9(-3/10) = 5

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3 years ago
Simplify the expression i⁸²
Elza [17]

Answer:

We can use a trick here. Let's look at the first few exponents of i to realize this:

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i^2= -1

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i^6 = -1

i^7 = -i

we can see that the pattern (1, i, -1, -i) repeats. Since 82/2 = 41, and 41 is only divisible by 1, i^41 = i, and i^2 = -1. -1*i = -i, so i^82 = -i.

Step-by-step explanation:

6 0
3 years ago
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