Answer:
<1= 60
<2=120
<3=60
<4=60
<5=120
<6=120
<7=60
Step-by-step explanation:
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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Volume is 4/3(3.14)(r)^2
the radius is 5.2 ft
2/3(2/8 + 4/8) = 2/3(1/4 + 1/2)
2/3(3/4) = 1/2
Answer:226.08 cubic feet
Step-by-step explanation:
π=3.14
Radius(r)=6feet
Height(h)=2feet
volume=π x r^2 x h
Volume=3.14 x 6^2 x 2
Volume=3.14 x 6 x 6 x 2
Volume=226.08
