Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
Can someone help me with my most recent question
Answer:?=3
Step-by-step explanation:
all you do is basic division... :)
Step 1:
Add rent & car payments
=11,250+1422
=$12,672
Step 2:
to determine %, set up a proportion
12,672 is to his total of 39,600 as x is to 100
12,672/39,600 = x/100
cross multiply
(12,672)(100) = (39,600)(x)
1,267,200= 39,600x
divide both sides by 39,600
32%= x
OR
Alternative Step 2:
12,672 ÷ 39,600= 0.32
Alternative Step 3:
0.32 x 100 = 32%
or move decimal to the right 2 places
His rent and car payments are 32% of his earnings.
Hope this helps! :)
