The complete question in the attached figure
we know that
If two secant segments are drawn to a <span>circle </span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.(Intersecting Secants Theorem)
5*(5+12)=6*(x+6)
5*17=6x+36
85=6x+36
6x=85-36
6x=49
x=49/6
x=8.17
the answer isx=8.17
The answer would be > now u can give the other person brainliest!
the 2nd one down.
y=3x+5
start at your y intercept (5) and use the rise to run ratio (rise 3, run 1) and there is a point on every single one.
1/3 wouldn't work because you rise 1 and go right 3 and that does not match any of the points
The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.
0 to 44 written in interval notation is [0,44].
The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.
A(t) = 9t
A = 9(44)
A = 396
With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.
0 to 396 written in interval notation is [0, 396].