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3 years ago

Use transformations to solve the equation. -24 = 3/8n

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

6 0

-24 = 3/8n

24*3=72

72/8=9

N=9

brilliants [131]3 years ago

6 0

Answer: n=-64 and -64=n *The answer should be the negative sign.*

Step-by-step explanation:

multiplication property of equality is multiplying both sides of an equation by the same number does not change equation.

a*c=b*c

switch sides of an equation.

3/8n=-24

multiply by 8 both sides of an equation.

8*3/8n=8(-24)

simplify.

3n=-192

divide by 3 both sides of an equation.

3n/3=-192/3

simplify by equation.

192/3=64

n=-64

Hope this helps!

Thanks!

Have a great day!

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nata0808 [166]

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3 years ago

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Ok so what do we know :

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4 years ago

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Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

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koban [17]

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