Given :
On a coordinate plane,a curved line with 3 arcs, lab led f of x, crosses the x-axis at (negative 2,0), (negative 1,0), (1,0), and (3,0) and the y axis at (0, negative 6).
To find:
f when x = 0. i.e. f (0).
Solution:
since the graph has 3 arcs and 4 solutions, it can be visualized as the follows:
Between each solution, the function has to increase and decrease giving arcs in between.
1. One of the arcs is between (negative 2,0) and negative (1,0)
2. Second arc is between (negative 1,0) and (1,0)
-this arc cuts the y axis, since x= 0 lies between x= -1 & x=1-
3. Third arc is between (1,0) and (3,0)
Therefore only the 2nd arc cuts the y axis
It’s given that the curve cuts the y axis at (0, -6)
That is when x= 0, f(0) =-6
Therefore the value of f (0) is -6 only.
HOPED THIS HELPED LUV!!
X^2 -5x -36 = x*x -9x+4x -9*4 = x(x-9) +4(x-9) = (x+4)(x-9)
so the second other factor is x+4 so hope that choice wan being x+4 than this will be right just you missed the sign pf plus
hope this will help you
Answer:
Step-by-step explanation:
For this exercise it is important to remember the following:
Given the following expression:
You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:
1. Replace with and simplify:
2. Descompose 12 into its prime factors:
3. Substitute into the expression:
4. Since , you can simplify it:
Answer:
Slope intercept formula is Y=MX +B
Step-by-step explanation:
so all you need to do is put the equation in that Form
THE SLOPE WOULD BE -8
Answer: 0.567
Step-by-step explanation: