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Sergeeva-Olga [200]
2 years ago
5

Beth can run 3 miles and 25.8 minutes how long does it take her to run 1 mile

Mathematics
1 answer:
agasfer [191]2 years ago
6 0
To solve this problem you need to use the cross product method!

3 miles → 25.8 minutes
1 mile → × minutes


→ (25.8 • 1) ÷ 3 = × minutes

→ 25.8 ÷ 3 = × minutes

→ 8.6 = × minutes

So your answer is that it takes beth 8.6 minutes to run 1 mile!

There you go! I really hope this helped, if there’s anything just let me know! ☻
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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean \mu=510,

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Percentage of students scored below 300 is given by,

P(Z\leq \frac{x-\mu}{\sigma})\times 100

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=0.0179\times 100

=1.79\%

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

P(x\leq t)=0.90

Now, P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90

P(Z< \frac{t-\mu}{\sigma})=0.90

\frac{t-\mu}{\sigma}=1.28

\frac{t-510}{100}=1.28

t-510=128

t=128+510

t=638

Score puts someone in the 90th percentile is 638.

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Step-by-step explanation:

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