Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,






Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,

Now, 






Score puts someone in the 90th percentile is 638.
Answer:
Using the Pythagorean Theorem:
distance^2 = 72^2 + 65^2
distance^2 = 5,184 + 4,225
distance^2 = 9,409
distance = 97 yards
"round-trip" distance = 97 * 2 = 194 yards
Step-by-step explanation:
It’s is 20,0000 but it think that’s wrong
We can use point slope form then convert to slope intercept
point slope
y-y1=m(x-x1)
m=slope
(x1,y1) is a givn point
point is (2,5)
slope is 3/4
y-5=3/4(x-2)
y-5=3/4x-6/2
add 5
y=3/4x-3+5
y=3/4x+2