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4 years ago

The interior angles of a hexagon are (2x+17)0, (3x - 25)0, (2x+49)0,

Mathematics

1 answer:

EleoNora [17]4 years ago

7 0

Answer: a) x= 68, b) 108°, c) 72°, d) 255°.

Step-by-step explanation:

Since we have given that

The interior angles of hexagon:

(2x+17), (3x - 25), (2x+49), (x+40), (4x-17) and (3x - 4).

So, it becomes :

$2x+17+3x-25+2x+49+x+40+4x-17+3x-4=1080\\\\15x+60=1080\\\\15x=1080-60\\\\15x=1020\\\\x=68$

ii. Find the smallest interior angle of the quadrilateral.

$x+40=68+40=108^\circ$

iii. Find the largest exterior angle of the quadrilateral.

$180-108=72^\circ$

iv. Find the largest interior angle of the quadrilateral.

$4x-17=4\times 68-17=255^\circ$

Hence, a) x= 68, b) 108°, c) 72°, d) 255°.

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3 years ago

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Step-by-step explanation:

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a. can never be equal to the value of the coefficient of determination (r2).

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False not always if r= 1 we have that $r^2 =1$ and we don't satisfy the condition

c. is always smaller than the value of the coefficient of determination (r2).

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