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padilas [110]
3 years ago
5

The interior angles of a hexagon are (2x+17)0, (3x - 25)0, (2x+49)0,

Mathematics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:  a) x= 68, b) 108°, c) 72°, d) 255°.

Step-by-step explanation:

Since we have given that

The interior angles of hexagon:

(2x+17), (3x - 25), (2x+49),  (x+40), (4x-17) and (3x - 4).

So, it becomes :

2x+17+3x-25+2x+49+x+40+4x-17+3x-4=1080\\\\15x+60=1080\\\\15x=1080-60\\\\15x=1020\\\\x=68

ii. Find the smallest interior angle of the quadrilateral.

x+40=68+40=108^\circ

iii. Find the largest exterior angle of the quadrilateral.

180-108=72^\circ

iv. Find the largest interior angle of the quadrilateral.

4x-17=4\times 68-17=255^\circ

Hence, a) x= 68, b) 108°, c) 72°, d) 255°.

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Answer:

Equation of Hanger A:

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Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

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So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

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weight of the square in Hanger A = z =?

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Similarly for Hanger B.

Equation for hanger B

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