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3 years ago

WILL GIVE BRIANIEST TO CORRECT ONLY

Mathematics

1 answer:

Neko [114]3 years ago

8 0

Answer:

a) 105

b) 75

c) 105

Step-by-step explanation:

a) supplementary angles. 180-75 is 105

b) 75. same as kings ave

c) supplementary angles. also vertical angles 180-75 is 105

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Anna can do a job in 4 days. After she has worked for 1 day, she is joined by Sylvia, and it takes them 2 days working together

Charra [1.4K]

Answer: 8 days.

Step-by-step explanation:

Given that Anna can do a job in 4 days. After she has worked for 1 day, she is joined by Sylvia, and it takes them 2 days working together to finish the job.

Since Anna has already worked for 1 day, she would have worked the remaining days for 3 days. But she is joined by Sylvia, and it takes them 2 days working together to finish the job.

That is,

1/3 + 1/S = 1/2

Where S is the number of days Sylvia to do the job being completed in 2 days.

1/S = 1/2 - 1/3

1/S = (3 - 2)/6

1/S = 1/6

S = 6

The job Anna would have done for 3 days, will take 6 days for Sylvia.

The 1 days used by Anna will be 2 days for Sylvia.

Therefore, the total days that will take Sylvia to do the whole job by herself will be 2 + 6 = 8 days

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3 years ago

What is the value of -2(x + 3)

matrenka [14]

Answer:

2x+6 period

5 0

3 years ago

How to find (c,d,e)<br>Please do a step by step working.Thank you.

Natasha2012 [34]

(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
   $\frac{t + 1}{2}$ = y
Answer for (a): $g^{-1}(t)$ = $\frac{t + 1}{2}$

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: $y =\frac{t - 3}{4}$

Answer for (b): $h^{-1}(t)$ = $\frac{t - 3}{4}$

(c)
$g^{-1} ( h^{-1}(t)) = g^{-1} (\frac{t - 3}{4})$
replace all t's in the $g^{-1}(t)$ equation with $\frac{t - 3}{4}$
$g^{-1} (\frac{t - 3}{4})$ = $\frac{ \frac{t-3}{4} + 1}{2}$
= $\frac{ \frac{t-3}{4} + \frac{4}{4}}{2}$ = $\frac{ \frac{t - 3 + 4}{4}}{2}$ = $\frac{ \frac{t + 1}{4}}{2} = \frac{t + 1}{8}$
Answer for (c): $g^{-1} ( h^{-1}(t))$ = $\frac{t + 1}{8}$

(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
   y = 8 t - 1
   t = 8y - 1
t + 1 = 8y
$\frac{t + 1}{8}$ = y
Answer for (e): inverse of h(g(t)) = $\frac{t + 1}{8}$

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