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Jobisdone [24]
4 years ago
11

What happens to the solubility of a typical solid solute as temperature increases?

Physics
1 answer:
lara31 [8.8K]4 years ago
7 0
For many solids<span> dissolved in liquid water, the </span>solubility increases<span> with </span>temperature<span>. </span>
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Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
NISA [10]
The mechanical advantage of a machine is the ratio between the output force and the input force:
MA= \frac{F_O}{F_I}
In our problem, the input force is 100 N, while the output force is the weight of the object the student lifts, 500 N. So, the mechanical advantage is
MA= \frac{500 N}{100 N}=5
7 0
4 years ago
Name three ways carbon and oxygen get into the environment.
Dafna1 [17]
Humans,trees,plants   hope it helps

7 0
4 years ago
A mass of 2.82 kg is hung from a spring, causing the spring to stretch 0.331 m. If a second mass of 3.09 kg is now added to the
irina1246 [14]

Answer:

0.694 m

Explanation:

Case 1 : When only mass of 2.82 kg is hanged from spring

m = mass hanged from the spring = 2.82 kg

x = stretch caused in the spring = 0.331 m

k = spring constant

Using equilibrium of force in vertical direction

Spring force = weight of the mass

k x = m g

k (0.331) = (2.82) (9.8)

k = 83.5 N/m

Case 2 : When both masses are hanged from spring

m = mass hanged from the spring = 3.09 + 2.82 = 5.91 kg

x = stretch caused in the spring = ?

k = spring constant = 83.5 N/m

Using equilibrium of force in vertical direction

Spring force = weight of the mass

k x = m g

(83.5) x = (5.91) (9.8)

x = 0.694 m

4 0
3 years ago
What is Structure C?<br><br><br> epiglottis<br><br> trachea<br><br> larynx<br><br> bronchi
finlep [7]

Answer:

it he answer is a trachea

4 0
4 years ago
A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.
iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2

Converting to m/s²

a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g

Hence, acceleration of the car is -0.64525g

8 0
4 years ago
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