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3 years ago

Can anyone help with these questions please

Physics

1 answer:

Svet_ta [14]3 years ago

6 0

Here... I've finished this course already

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Convert 2m^2 to in^2<br><br> show work

nalin [4]

Explanation:

$1m \: = 39.4 \: in \\ \\ 2 {m}^{2} . \frac{39.4 \: in}{1 \: m} . \frac{39.4 \: in}{1 \: m} = 3104.7 \: {in}^{2}$

5 0

4 years ago

A cat walks 15 m north and then 12 m south. What distance did the cat walk?

alekssr [168]

Answer:

it's 27 meters - answer B

3 0

3 years ago

An astronaut drops a marble on the surface of Mars and observes that it takes 1.02 s for the marble to fall 2.00 m. She also kno

Irina-Kira [14]

Answer:

The mass of mars is $6.61\times10^{23}\ kg$

Explanation:

Given that,

Time = 1.02 s

Height = 2.00 m

Radius of mars $r= 3.39\times10^{6}\ m$

We need to calculate the acceleration due to gravity on mars

Using equation of motion

$h = ut+\dfrac{1}{2}gt^2$

$h = \dfrac{1}{2}gt^2$

$g=\dfrac{2h}{t^2}$

Where, u = initial velocity

t = time

h = height

Put the value into the formula

$g=\dfrac{2\times2.00}{(1.02)^2}$

$g=3.84\ m/s^2$

We need to calculate the mass of mars

Using formula of gravity

$g=\dfrac{Gm}{r^2}$

Put the value into the formula

$3.84=\dfrac{6.67\times10^{-11}\times m}{(3.39\times10^{6})^2}$

$m=\dfrac{3.84\times(3.39\times10^{6})^2}{6.67\times10^{-11}}$

$m=6.61\times10^{23}\ kg$

Hence, The mass of mars is $6.61\times10^{23}\ kg$

5 0

3 years ago

If the neutron microscopic absorption cross section of boron at 0.0253 eV is 3847 barns, what would it be at 0.1 eV? [ Ans. 1935

Bingel [31]

Answer:

The correct answer will be "1935 barns".

Explanation:

The given values are:

$E_{1}$ = 0.0253 eV

$E_{2}$ = 0.1 eV

$\sigma_{2}$ = 3847 barns

Now,

⇒ $\frac{\sigma_{1}}{\sigma_{2}} = \frac{E_{1}}{E_{2}}$

then,

⇒ $\sigma_{1}=\sigma_{2}\sqrt{\frac{E_{1}}{E_{2}}$

On substituting the given values, we get

⇒ $=3847\times \sqrt{\frac{0.0253}{0.1} }$

⇒ $=1935 \ barns$

8 0

4 years ago

What is the missing number in the nuclear reaction shown below?

sergey [27]

Answer:

$\boxed{299}$

Explanation:

In this reaction, Sum of Atomic Masses of Left side = Sum of Atomic Masses of right side

Let the atomic mass of Thorium be x

So,

233 = 4 + x

Subtracting 4 to both sides

x = 233-4

x = 229

5 0

3 years ago