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Naddika [18.5K]
4 years ago
5

When an electron jumps from high-to low-energy levels:

Physics
1 answer:
AysviL [449]4 years ago
5 0

Answer:

B. A wave of visible light is produced.

Explanation:

The visible light spectrum is in the centre of the Electromagnetic Spectrum, so any time an electron jumps from high to low levels of radiation, it has to cross through the visible spectrum.

I hope this is correct, and as always, I am joyous to assist anyone at any time.

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Suppose that a spring with a larger spring constant was used in this same apparatus. If a given mass were rotated at the same ra
malfutka [58]

Answer:

The new period of rotation using the new spring would be less than the period of rotation using the original spring

Explanation:

Generally the  period of rotation of the mass is mathematically represented as

       T = 2 \pi \sqrt{\frac{I}{k} }

Here I is the moment of inertia of the mass about the rotation axis and  k is the spring constant

Now looking at the equation we can tell that T is inversely proportional to the square root of the spring constant which means that for a larger spring constant the time period would be lesser

6 0
3 years ago
What is the next step if the data from an investigation do not support the original hypothesis? A. The data are revised to suppo
Leno4ka [110]
I believe the answer is D. <span>The hypothesis is revised and another experiment is conducted.</span>
5 0
4 years ago
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12. A concave lens has a focal length of 10 cm. An object 2.5 cm high is placed 30 cm from the lens. Determine the position and
Nimfa-mama [501]

Answer:

I think 9.5

Explanation:

............

6 0
3 years ago
How can you change the phases of matter using thermal energy
Leokris [45]

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance.

8 0
3 years ago
A bullet is fired horizontally from a handgun at a target 100.0 m away. If the initial speed of the bullet as it leaves the gun
Lera25 [3.4K]

Answer:

The distance is 0.53 m.

Explanation:

Given that,

Target distance = 100.0 m

Speed of bullet = 300 m/s

We need to calculate the total time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{100.0}{300}

t=0.33\ sec

Now, consider vertical motion of bullet.

Initial velocity of bullet in vertical direction = 0 m/s

We need to calculate the vertically distance

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

s=0+\dfrac{1}{2}\times9.8\times(0.33)^2

s=0.53\ m

Hence, The distance is 0.53 m.

5 0
4 years ago
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