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kifflom [539]
2 years ago
5

The propagation of an action potential (AP) in an unmyelinated axon is called continuous propagation. This activity will test yo

ur understanding of the sequence of events that occur during continuous propagation.
Place the following events involved in the propagation of an action potential in the correct order of occurrence from left to right:
A) Voltage Gated Na+ channels open
B) Influx of Na+
C) Local current flows to axon segment
D) Axon segment depolarized to threshold
E) AP generated in adjacent axon segment
Biology
1 answer:
Dimas [21]2 years ago
3 0

Answer:

C, D, A, B, E

Explanation:

The sudden decrease or increase in the potential of cell membrane is Action potential. The stimulus (local current) allows change in the membrane potential, thus allowing depolarization of the membrane. This initiates the opening of Voltage Gated Na+ channels. The sodium starts entering the cell that is influx of Na+ and thus AP generated in adjacent axon segment. The sodium channels inactivates by membrane repolarization and activated pottassium channels allows the efflux of pottassium ions. The inactivation of potassium channels occurs by hyperpolarization ( low membrane potential) brings the membrane to its resting state. Thus, the correct order is C, D, A, B, E.

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A plant has the genotype AAbbCcDDEeff, where each letter represents a different gene. This plant is crossed with another whose g
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Answer:

The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%

Explanation:

You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:

Cross) AAbbCcDDEeff     x      AaBBCcddEEFF

Cross For each gene by separately:

  • Parental )        AA    x    Aa

       Gametes)  A    A         A    a

        F1)             2/4 AA  

                          2/4 Aa

  • Parental )        bb    x    BB

         Gametes)  b    b         B   b

          F1)                   4/4 Bb

  • Parental )        Cc    x    Cc

        Gametes)  C    c         C    c

         F1)             1/4 CC

                           2/4 Cc

                            1/4 cc

  • Parental )        DD    x    dd

       Gametes)  D    D          d    d

        F1)             4/4 Dd

  • Parental )        Ee    x    EE

        Gametes)     E     e      E     E

         F1)             2/4 Ee

                           2/4 EE

  • Parental )        ff    x    FF

         Gametes)     f     f      F     F

          F1)             4/4 Ff

So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:

4/4 A-  x  4/4 Bb   x   1/4 cc   x   4/4 Dd   x  4/4 E-   x   4/4 Ff =  

1024/4096 = 0.25 A-BbccDdE-Ff =25%  

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