9514 1404 393
Answer:
0
Step-by-step explanation:
If a=b, you are asking for a whole number c such that ...
c = √(a² +a²) = a√2
If 'a' is a whole number, the only whole numbers that satisfy this equation are ...
c = 0 and a = 0.
0 = 0×√2
The lowest whole number c such that c = √(a²+b²) and a=b=whole number is zero.
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√2 is irrational, so there cannot be two non-zero whole numbers such that c/a=√2.
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<em>Additional comment</em>
If you allow 'a' to be irrational, then you can choose any value of 'c' that you like. Whole numbers begin at 0, so 0 is the lowest possible value of 'c'. If you don't like that one, you can choose c=1, which makes a=(√2)/2 ≈ 0.707, an irrational number. The problem statement here puts no restrictions on the values of 'a' and 'b'.
X^2 + 6x + 3 = 0
a=1, b=6, c=3
x1=[-6+sqrt (6^2-4*1*3)] / (2*1)
=[-6+sqrt (24)] / (2)
=-0.55
x2==[-6-sqrt (6^2-4*1*3)] / (2*1)
=[-6-sqrt (24)] / (2)
=-5.45
answer A
Answer:
Step-by-step explanation:
2x-5y=8. y = 2/5x-8/5
Line q: (-6,2). Slope -5/2
y-2 = -5/2(x- - 6). y-2 = -5/2(x+6)
y-2 = - 5/2x - 6
y = -5/2x -6 +2
y = - 5/2x - 4
Answer:x= 5
Step-by-step explanation:
5x-12=63
>5x=63+12=75
>x=75÷5
>x=15
Answer:
<h2><em>
T O M E I T L O O K S A B O U T R I G H T.</em></h2>
Step-by-step explanation:
