In order to see how many real roots it has you have to see what the Δ is
So if Δ>0 then there are 2 real roots
If Δ=0 there is 1 real root
If Δ<0 no real root
And we know that:
Δ=b^2-4ac
So in the equation: Δ=b^2+4 and b^2 is always a number greater than or equal to 0 so when you add 4 to it, it is always greater than 0
So it has 2 real roots
Step-by-step explanation:
d=2r
πr^2
10/2=r
5=r
5^2π
25π=78.5398
Hope that helps :)
Answer:
a=3 IF it's continuos
Step-by-step explanation:
for continuity, the left limit of the first equation must be equal to the right limit of the third equation
and they are equal, as you can see putting x=2 in both equations
to be continuos in a point c, f(x) must:
be defined in c (so f(c) exists)
the limit in c exists (in this case both from left and right)
the limit in c must be equal to f(c)
Answer:
D r = 4 − 4 cos(θ)
Step-by-step explanation:
Right on edge
Answer:
(6, 2)
Step-by-step explanation:
i hope this helps :)