X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
(i think) 1.5
Step-by-step explanation:
If you replace y with the equation y=2x-3, you get 5(2x - 3)
if you distribute this, it equals 10x - 15
combining like terms 10x + 10x - 15=15 will turn into 20x - 15 = 15
if you add 15 to both sides, -15 will cancel and 15 will turn into 30
20x = 30
divide both sides by 20 which will lead to x=1.5
Unfortunately, you haven't shared the equations from which you're supposed to choose your answer.
But we can write our own.
When will the distance traveled by the 1st car = the distance traveled by the 2nd car?
55 miles + (55 mph)x = (60 mph)x
solve this for x: 55 miles = (60-55)x mph = 5 mph
x=11 hours
The two cars are the same distance from the starting point after 11 hours.
We need to follow PEMDAS
So
167So... none of your answer choices are correct.
A. Equation of line l: y = mx + 20 where m = y' = 1- (1/250)x
At the point Q, The equation of the line equals the equation of the parabola.
So (1-x/250)x + 20 = x - x^2/500
20 = x^2/250 - x^2/500 = x^2/500
x = sqrt(20*500) = 100ft
B. m = 1 - 100/250 = 3/5.
<span>Equation of line L is y = 3/5x + 20
</span>
C) If a spotlight is located at the x intercept of line L (-33 1/3,0), its light will go only above line L past the point where line L is tangent to the hill at (100,80) because the hill blocks the light below the tangent line.
<span>The highest point on the equation of y = x - x²/500 is at (250,125), so a tree 50 feet tall at that location would reach up to (250,175). The tangent line goes through (250,170), so the top 5 feet of the tree would be above the tangent line, in the glow of the spotlight.
</span>
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