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sineoko [7]
3 years ago
13

Many bank accounts never go below zero. But some banks will allow a negative balance, at least for a short time, called an overd

raft. It means someone has taken out, or 'drafted', more money than was in the account to begin with. Joshua's account went into overdraft. To get back to a positive balance, he deposited money at a steady rate of $22.5 per week. After 4 weeks, he had $69.21 in the account. What was the balance when the account went into overdraft?
Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

46.71 is the answer i hope it will help u .

Step-by-step explanation:

u just subtract the deposited money with he had in 4 week : ) i guss

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The CEO of a large manufacturing company is curious if there is a difference in productivity level of her warehouse employees ba
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Answer:

The test statistic is z = -2.11.

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Group 1: Sample of 35, mean of 1276, standard deviation of 347.

This means that:

\mu_1 = 1276, s_1 = \frac{347}{\sqrt{35}} = 58.6537

Group 2: Sample of 35, mean of 1439, standard deviation of 298.

This means that:

\mu_2 = 1439, s_2 = \frac{298}{\sqrt{35}} = 50.3712

Test if there is a difference in productivity level.

At the null hypothesis, we test that there is no difference, that is, the subtraction is 0. So

H_0: \mu_1 - \mu_2 = 0

At the alternate hypothesis, we test that there is difference, that is, the subtraction is different of 0. So

H_1: \mu_1 - \mu_2 \neq 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = \mu_1 - \mu_2 = 1276 - 1439 = -163

s = \sqrt{s_1^2+s_2^2} = \sqrt{58.6537^2+50.3712^2} = 77.3144

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{-163 - 0}{77.3144}

z = -2.11

The test statistic is z = -2.11.

7 0
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Answer:

60,120,180

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Step-by-step explanation:

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Explanation:

First, add by 25 both sides of an equation.

-25+t+25=-44+25

Then, simplify by equation and add/subtract by the numbers.

44-25=19

*The answer must be have a negative sign.

\boxed{t=-19}

Hope this helps!

Thank you!

Have a great day!

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Andreyy89

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On the other hand, let {s_n-L} be a sequence that converges to 0. This means |(s_n-L)-0| for all large enough n, and we get the simpler inequality for free, |s_n-L|, so it follows that s_n\to L.

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