Answer:
Option D. 13122 is the answer.
Step-by-step explanation:
As we can see from the table having interval and average rate of change, figures under average rate of change are forming a geometric sequence.
Sequence is 2, 6, 18 , 54, 162, 486.
and we have to find the average rate of change from x = 8 to x = 9, means we have to find 9th term of the given sequence.
Now we know that explicit formula of the sequence can be written as 
where Tn is the nth term of the sequence.
a = first term
r = common ratio
n = number of the term
Now from this explicit formula we can find the 9th term of the sequence.
From the given table
a = 2, r = 3, n = 9
T9 = 13122
Therefore Option D. 13122 will be the answer.
5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0, then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get -- 40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)
Answer: a) y = f(x - 6)
b) y = f(x) - 2
<u>Step-by-step explanation:</u>
For transformations we use the following formula: y = a f(x - h) + k
- a = vertical stretch
- h = horizontal shift (positive = right, negative = left)
- k = vertical stretch (positive = up, negative = down)
a) f(x) has a vertex at (-1, 1)
M has a vertex at (5, 1)
The vertex shifted 6 units to the right → h = +6
Input h = +6 into the equation and disregard "a" and "k" since those didn't change. ⇒ y = f(x - 6)
b) f(x) has a vertex at (-1, 1)
N has a vertex at (-1, -1)
The vertex shifted down 2 units → k = -2
Input k = -2 into the equation and disregard "a" and "h" since those didn't change. ⇒ y = f(x) - 2
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
