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lyudmila [28]
3 years ago
7

How many sigma and pi bonds are present in the molecule hcn?

Chemistry
1 answer:
Leni [432]3 years ago
8 0

Answer:

Hydrogen cyanide (HCN) contains two (2) sigma bonds and two (2) pi bonds.

Explanation:

Hydrogen cyanide can be represented structurally as :

H-C≡ N

From the structural formula, we can see:

One C-H sigma bond

While the  C≡ N bond contains One Sigma and two (2) pi bonds.

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(3.605 X 10^-27) + (4.01 X 10^-25)<br> Answer in scientific notation
Greeley [361]
The answer is 4.04605 X 10^-25
3 0
3 years ago
a sample of argon gas is cooled and its volume went from 380. mL to 250. mL. If its final temperature was -55.0C, what was its o
inn [45]

Answer:

The initial temperature was 58.4°C

Explanation:

Given the following data:

initial volume = V₁ = 380 mL = 0.38 L

final volume = V₂ = 250 mL = 0.25 L

final temperature = T₂ = -55°C = 218 K

According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:

V₁/T₁= V₂/T₂

So, we calculate the initial temperature (V₁) as follows:

T₁ = T₂/V₂ x V₁ = 218 K/(0.25 L) x 0.38 L = 331.36 K ≅ 331.4 K

Finally, we convert the initial temperature from K to °C:

T₁= 331.4 K - 273 = 58.4°C

6 0
3 years ago
In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
3 years ago
How many moles are in 1.86•10^23 F atoms?
Goryan [66]

Answer: .309 moles (rounded to the nearest thousandth)

Explanation: divide your atoms by (6.022 x 10x^{23})

3 0
3 years ago
What is the oxidation state of each element in S03^2-?
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Mycraf I fink? Sory is wrong

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