How many moles are in 1.86•10^23 F atoms?

A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed

AlekseyPX

(a) 4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 20.68N_2;

(b) 4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2;

(c) 23 900 kg air; (d) air:fuel = 10.2; (e) air:fuel = 12.2:1

(a) Balanced equation including N_2 from air

The balanced equation ignoring N_2 from air is

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2

Moles of N_2 =55 mol O_2 × (3.76 mol N_2/1 mol O_2) = 206.8 mol N_2

Including N_2 from air, the balanced equation is

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 206.8N_2

(b) Balanced equation for 120 % stoichiometric combustion

Moles of O_2 = 55 mol O_2 × 1.20 = 66.00 mol O_2

Excess moles O_2 = (66.00 – 55) mol O_2 = 11.00 mol O_2

Moles of N_2 = 66.00 mol O_2 × (3.76 mol N_2/1 mol O_2) = 248.2 mol N_2

The balanced equation is

4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2

(c) Minimum mass of air

Moles of O_2 required = 1700 kg C_11 H_7S

× (1 kmol C_11 H_7S/185.24 kg C_11 H_7S) × (55 kmol O_2/4 kmol C_11 H_7S)

= 126.2 kmol O_2

Mass of O_2 = 126.2 kmol O_2 × (32.00 kg O_2/1 kmol O_2) = 4038 kg O_2

Mass of N_2 required = 126.2 kmol O_2 × (3.76 kmol N_2/1 kmol O_2)

× (28.01 kg N_2/1 kmol N_2) = 13 285 kg N_2

Mass of air = Mass of N_2 + mass of O_2 = (4038 + 13 285) kg = 17 300 kg air

(d) Air:fuel mass ratio for 100 % combustion

Air:fuel = 17 300 kg/1700 kg = 10.2 :1

(e) Air:fuel mass ratio for 120 % combustion

Mass of air = 17 300 kg × 1.20 = 20 760 kg air

Air:fuel = 20 760 kg/1700 kg = 12.2 :1

6 0

3 years ago

An oxygen molecule consists of two oxygen atoms, (O2), whose total mass is 5.3 × 10–26 kg and whose moment of inertia about an a

Katena32 [7]

Answer : The distance between the two atoms is $1.2\times 10^{-10}m$

Explanation :

The The formula used for moment of inertia for one atom is:

$I=(\frac{m}{2})r^2$

The formula used for moment of inertia for two atom is:

$I=2(\frac{m}{2})r^2$

where,

I = moment inertia = $1.9\times 10^{-46}kg.m^2$

r = distance of atom from axis of rotation

m = mass of atom = $5.3\times 10^{-26}kg$

Now put all the given values in the above formula, we get:

$I=2(\frac{m}{2})r^2$

$1.9\times 10^{-46}kg.m^2=2(\frac{5.3\times 10^{-26}kg}{2})r^2$

$r=6.0\times 10^{-11}m$

Now we have to calculate the distance between the two atoms.

Formula used :

$d=2r$

where,

d = distance between the two atoms

$d=2\times 6.0\times 10^{-11}m=1.2\times 10^{-10}m$

Therefore, the distance between the two atoms is $1.2\times 10^{-10}m$

3 0

4 years ago

(8 pts) Give the answers that should be filled in the blanks below:

Olegator [25]

Answer:

[H⁺] = 1.58x10⁻⁶M; [OH⁻] = 6.31x10⁻⁹M.

pH = 8.23; pOH = 5.77

Explanation:

pH is defined as -log [H⁺] and also you have 14 = pH + pOH

Thus, for a solution of pH = 5.80.

5.80 = -log [H⁺] → [H⁺] = 10^-(5.80) = 1.58x10⁻⁶M

pOH = 14-5.80 = 8.20 → [OH⁻] = 10^-(8.20) = 6.31x10⁻⁹M

Thus, for a solution of [H⁺] = 5.90x10⁻⁹M and pH = -log 5.90x10⁻⁹M = 8.23

And pOH = 14-8.23 = 5.77

6 0

3 years ago

What did timbuktu contributed to mali's important as a kingdom

Alex73 [517]

Timbuktu was considered a MASSIVE trade center in Mali. That is how all of the foreign goods came into the kingdom. It also had education centers which was very important in Mali.

5 0

3 years ago

Read 2 more answers

What happened to Jodys father

Lady bird [3.3K]

Answer:

Jody's father was bitten by a poisonous snakes name rattle snake

3 0

3 years ago