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inna [77]
3 years ago
5

Using the balanced equation for the combustion of ethane: 2C2H6 + 7O2 → 4CO2 + 6H2O, how many moles of O2 needed to produce 12 m

oles of H2O?
Chemistry
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

14 moles of oxygen needed to produce 12 moles of H2O.

Explanation:

We are given that balance eqaution

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

We have to find number of moles of O2 needed  to produce 12 moles of H2O.

From given equation

We can see that

6 moles of   H2O produced by Oxygen =7 moles

1 mole of   H2O produced by Oxygen=\frac{7}{6}moles

12 moles of H2O produced by Oxygen=\frac{7}{6}\times 12moles

12 moles of H2O produced by Oxygen=7\times 2moles

12 moles of H2O produced by Oxygen=14 moles

Hence, 14 moles of oxygen needed to produce 12 moles of H2O.

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4 years ago
Calculate the volume of concentrated HCl (12 M) needed to convert the sodium benzoate back to benzoic acid.
iVinArrow [24]

The question is incomplete, the complete question is;

Calculate the volume of concentrated HCL (12 M) needed to convert 1.5 g of sodium benzoate back to benzoic acid.

Answer:

8.33 * 10^-4 L

Explanation:

Equation of the reaction;

C6H5COONa + HCl -------->>>> C6H5COOH + NaCl

Number of moles of  sodium benzoate = mass/molar mass

molar mass of sodium benzoate =144.11 g/mol

mass of sodium benzoate = 1.5 g

Number of moles of  sodium benzoate = 1.5g/144.11 g/mol

Number of moles of  sodium benzoate = 0.01 moles

Since the reaction is 1:1,  0.01 moles of HCl reacted.

but;

n = CV

n = number of moles

C = concentration

V = volume

V = n/C

V =  0.01 moles/12 M

V = 8.33 * 10^-4 L

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