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professor190 [17]
3 years ago
8

2. The cost that a carpet cleaning company charges is directly proportional to the number of rooms cleaned. The cost is $22 for

each room.
(a) Write a direct variation equation to represent the cost.
(b) How many rooms can a hotel pay the company to clean for $200? Write and solve an equation.
(c) Suppose the hotel plans to tip the carpet cleaners $40, how many rooms can the hotel get cleaned for $200 now? Write and solve an equation.
Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0
(a) y=22x
(b) 200=22x
      9.09=x   (round down to whole number)
      9=x
(c) 200=22x+40
      160=22x
      7.27=x     (round down)
      7=x
kvv77 [185]3 years ago
5 0
<span>The cost that a carpet cleaning company charges is directly proportional to the number of rooms cleaned. The cost is $22 for each room.</span>
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The difference 25(d−10)−23(d+6)25(d−10)−23(d+6) is
MArishka [77]
25d - 250 | - 575d^2 + 2277d + 34362
8 0
3 years ago
Read 2 more answers
3. The rectangle below has an area of 297 in. Find the length of the diagonal.
saul85 [17]

9514 1404 393

Answer:

  29.15 in

Step-by-step explanation:

The area of a rectangle is given by the formula ...

  A = LW

Filling in the given information, we can find the missing side length.

  297 in² = (27 in)h

  h = (297 in²)/(27 in) = 11 in

The length of the diagonal can be found from the Pythagorean theorem.

  d² = 27² + 11² = 729 +121 = 850

  d = √850 = 5√34 ≈ 29.15476

The length of the diagonal is about 29.15 inches.

7 0
3 years ago
Can someone give me an answer for this?
stealth61 [152]

Answer:

444 adult ticket

763 student ticket

Step-by-step explanation:

let a = number of adult ticket

let s = number of student ticket

s+a=1207

5a+s=2983

get s by itself in the 1st equation so you can plug it into the 2nd

s+a=1207

-a      -a

s=1207-a

5a+(1207-a)=2983

solve for a

4a+1207=2983

-1207      -1207

4a= 1776

444

this is adult ticket amount

subtract this from 1207 to get student amount

1207-444=763

8 0
3 years ago
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
2/15 + 27/35 = what in reduced terms
solniwko [45]

2/15 + 27/35 = 14+81 /105 = 95/105 = 19/21

so, your answer is 19/21

8 0
3 years ago
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