Answer:
Undefined
Step-by-step explanation:
has a slope of
, since it is a horizontal line. The only types of lines that are perpendicular to horizontal lines are vertical lines, which are usually in the form
(where
is any real number). Vertical lines have an undefined slope, so the answer is undefined. Hope this helps!
Answer:

Step-by-step explanation:
Given
![\sqrt[3]{217}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B217%7D)
Required
Solve
Linear approximated as:

Take:

So:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Substitute 216 for x
![f(x) = \sqrt[3]{216}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7B216%7D)

So, we have:



To calculate f'(x);
We have:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Rewrite as:

Differentiate

Split


Substitute 216 for x



So:





Answer:
765 miles
Step-by-step explanation:
Find the rate (mph) and then multiply the result by 9 hours:
340 mi
------------- * 9 hrs = 765 miles
4 hrs