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S_A_V [24]
3 years ago
5

Please help Due in 3 Min!

Mathematics
1 answer:
iren2701 [21]3 years ago
7 0
The answer is 32 I really hope this helps with
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Which pair of ratios form a proportion?
Roman55 [17]
Your answer is B::))


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3 years ago
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Need help with trigonometry
vovangra [49]

Answer:

\sf \tan(A) & =\dfrac{9\sqrt{22}}{44}

Step-by-step explanation:

If angle C is the right angle, then side c is the hypotenuse.

Use Pythagoras' Theorem a^2+b^2=c^2 to find the length of side a:

Given:

  • b = 2√22
  • c = 13

\implies a^2+(2 \sqrt{22})^2=13^2

\implies a^2+88=169

\implies a^2=81

\implies a=\sqrt{81}

\implies a=9

<u>Tan Trig Ratio</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = A
  • O = side opposite angle A = a = 9
  • A = side adjacent angle A = b = 2√22

\begin{aligned}\implies \sf \tan(A) & =\dfrac{9}{2\sqrt{22}}\\\\ & =\dfrac{9}{2\sqrt{22}} \times \dfrac{\sqrt{22}}{\sqrt{22}}\\\\ & = \dfrac{9\sqrt{22}}{44} \end{aligned}

6 0
2 years ago
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HELP PLEASE I WILL GIVE BRAINLIEST!!!!
devlian [24]

Answer:

Would you mind posting a picture instead thank you.

4 0
3 years ago
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For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
Help please look below
Gwar [14]
A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A
3 0
2 years ago
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