<span>4^2 x 4^8 = 4^(2+8) = 4^10
hope it helps</span>
Answer:
7. ∠CBD = 100°
8. ∠CBD = ∠BCE = 100°; ∠CED = ∠BDE = 80°
Step-by-step explanation:
7. We presume the angles at A are congruent, so that each is 180°/9 = 20°.
Then the congruent base angles of isosceles triangle ABC will be ...
∠B = ∠C = (180° -20°)/2 = 80°
The angle of interest, ∠CBD is the supplement of ∠ABC, so is ...
∠CBD = 180° -80°
∠CBD = 100°
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8. In the isosceles trapezoid, base angles are congruent, and angles on the same end are supplementary:
∠CBD = ∠BCE = 100°
∠CED = ∠BDE = 80°
The sum of opposite angles are equal, so two of the angles are 45°. The sum of all angles about the intersection of two lines is 360°. So the remaining two angles are found by:
α=(360-2*45)/2
α=135° thus all four angles are:
45°,135°,45°,135°
