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3 years ago

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The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times t

he first. What are the numbers?
Which three expressions could be used to represent the numbers?

1 answer:

Burka [1]3 years ago

5 0

Hello,

Let's assume a,b,c the 3 numbers

a+b+c=62
b=a-4
c=4*a

==>a+(a-4)+4a=62
==>6a=66
==>a=11
b=11-4=7
c=4*11=44
The 3 numbers are 11;7;44

Proofs:
11+7+44=62
7=11-4
44=4*11

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Can someone please help me with my maths question

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Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

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Answer if u love cats & dogs

eimsori [14]

Answer:

<em>(7, 5.25)</em> lies on the graph.

Step-by-step explanation:

We are given the following values

x = 4, 6, 8, 12 and corresponding y values are:

y = 3, 4.5, 6, 9

Let us consider two points (4, 6) and (6, 4.5) and try to find out the equation of line.

Equation of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given as:

$y=mx+c$

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c is the y intercept.

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So, final equation of given function is:

$y=\dfrac{3}{4}x$

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As per the given options, the point <em>(7, 5.25) </em>satisfies the equation.

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