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3 years ago

10

Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor

rió?

1 answer:

Lemur [1.5K]3 years ago

7 0

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

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Describe some precautions needed to increase the safety of participants in the sports of football.

OLga [1]

Football is a popular ball game and so many people play football these days. Been a contact game, there is no way players will not sustain injuries, but this can be reduced to the lowest point by taking some precautions.
The precautions that could be taken include the following:
Wear the right shoes.
Wear shin guard and soccer socks.
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3 years ago

A trolley at rest is pushed to accelerate at a

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V^2 = 2a S
V = square root ( 2 x 0.5 . 4)
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Answer is B

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3 years ago

A 2.00 kg steel gas can holds 25.0 L of gasoline when full. What is the average density (in kg/m3) of the full gas can, taking i

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Answer:80kg/m^3

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3 years ago

Read 2 more answers

A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius pulley at the top

adoni [48]

Answer:

$I = 0.083 kg m^2$

Explanation:

Mass of the bucket, m = 23 kg

Radius of the pulley, r = 0.050 m

The bucket is released from rest, u = 0 m/s

The time taken to fall, t = 2 s

Speed, v = 8.0 m/s

Moment of Inertia of the pulley, I = ?

Using the equation of motion:

v = u + at

8 = 0 + 2a

a = 8/2

a = 4 m/s²

The relationship between the linear and angular accelerations is given by the equation:

$a = \alpha r$

Angular acceleration, $\alpha = a/r$

$\alpha = 4/0.050\\\alpha = 80 rad/s^2$

Since the bucket is falling, it can be modeled by the equation:

mg - T = ma

T = mg - ma = m(g-a)

T = 23(9.8 - 4)

The tension, T = 133.4 N

The equation for the pulley can be modeled by:

$T* r = I * \alpha\\133.4 * 0.050 = I * 80\\6.67 = 80 I\\I = 6.67/80\\I = 0.083 kg m^2$

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3 years ago

Please help me with this physics question!

Vadim26 [7]

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4 years ago