Answer:
216 units
Explanation:
F1 = kQ1Q2/r^2 = 36 (Coulomb's law)
F2 = k(2Q1)(3Q2)/r^2
= 6[kQ1Q2/r^2]
= 6F1
= 6 x 36
= 216 units
Explanation:
The magnitude of a vector v can be found using Pythagorean's theorem.
||v|| = √(vₓ² + vᵧ²)
||v|| = √((-309)² + (187)²)
||v|| ≈ 361
You can find the angle of a vector using trigonometry.
tan θ = vᵧ / vₓ
tan θ = 187 / -309
θ ≈ 149° or θ ≈ 329°
vₓ is negative and vᵧ is positive, so θ must be in the second quadrant. Therefore, θ ≈ 149°.
First we need to calculate the acceleration of the blood. Since we know the initial speed of the blood (0 m/s), the final speed (1 m/s) and the time (0.2 s), we can find the acceleration which is given by
Then we can use Newton's second law, which states that the force on the blood is
where
is the mass of the blood. Using these data, we find the average force:
Answer:
2.94 x 10⁵ Pa
Explanation:
m = mass of the car supported by four ires = 1200 kg
g = acceleration due to gravity = 9.8 m/s²
A = Area of contact for each tire = 100 cm² = 100 x 10⁻⁴ m²
n = Number of tires
P = Gauge pressure
Using equilibrium of force in vertical direction
n P A = mg
4 P (100 x 10⁻⁴) = (1200) (9.8)
P = 2.94 x 10⁵ Pa