Answer:
The mass of the ice block is equal to 70.15 kg
Explanation:
The data for this exercise are as follows:
F=90 N
insignificant friction force
x=13 m
t=4.5 s
m=?
applying the equation of rectilinear motion we have:
x = xo + vot + at^2/2
where xo = initial distance =0
vo=initial velocity = 0
a is the acceleration
therefore the equation is:
x = at^2/2
Clearing a:
a=2x/t^2=(2x13)/(4.5^2)=1.283 m/s^2
we use Newton's second law to calculate the mass of the ice block:
F=ma
m=F/a = 90/1.283=70.15 kg
<em>If the force squeezing two surfaces together is decreased, the force of dry sliding friction between the two surfaces will most likely decrease. </em>
<u>therefore your answer is B)</u><u>d</u><u>e</u><u>crease </u>
Hope this helps you- have a good day bro cya)
Answer:
Explanation:
tha question is too hard simplfy it fast
I will go to school tomorrow .....is this present tense or past tense or future tense
<span>an unbalanced force is Forces that are not equal</span>
