Answer: The riders are subjected to 11.5 revolutions per minute
Explanation: Please see the attachments below
The Yerkes refracting telescope has a 1.00 m diameter objective lens of focal length 20.0 m. Assume it is used with an eyepiece
1 answer:
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Explanation:
Consider the kinematic equation,
where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,
through simple algebra we get
where this is the distance traveled in meters.
Answer:
a) Em₀ = 42.96 104 J
, b) = -2.49 105 J
, c) vf = 3.75 m / s
Explanation:
The mechanical energy of a body is the sum of its kinetic energy plus the potential energies it has
Em = K + U
a) Let's look for the initial mechanical energy
Em₀ = K + U
Em₀ = ½ m v2 + mg and
Em₀ = ½ 50.0 (1.20 102) 2 + 50 9.8 142
Em₀ = 36 104 + 6.96 104
Em₀ = 42.96 104 J
b) The work of the friction force is equal to the change in the mechanical energy of the body
= Em₂ -Em₀
Em₂ = K + U
Em₂ = ½ m v₂² + m g y₂
Em₂ = ½ 50 85 2 + 50 9.8 427
Em₂ = 180.625 + 2.09 105
Em₂ = 1,806 105 J
= Em₂ -Em₀
= 1,806 105 - 4,296 105
= -2.49 105 J
The negative sign indicates that the work that force and displacement have opposite directions
c) In this case the work of the friction going up is already calculated in part b and the work of the friction going down would be 1.5 that job
We have that the work of friction is equal to the change of mechanical energy
= ΔEm
= Emf - Emo
-1.5 2.49 10⁵ = ½ m vf² - 42.96 10⁴
½ m vf² = -1.5 2.49 10⁵ + 4.296 10⁵
½ 50.0 vf² = 0.561
vf = √ 0.561 25
vf = 3.75 m / s
Answer:
The question is incomplete, below is the complete question
"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.
A) What is the frequency of this wave?
B) What is the wavelength of this wave?
C) What is the speed of this wave?"
Answers:
a.
b.
c.
Explanation:
The equation of a wave is represented as
Where A=amplitude
w=angular frequency=2πf
K=wave numbers =2π/λ
since we re giving he equation D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),
we can compare and get the value for the wave number and angular frequency.
By comparing we have
w=60rads/s
k=6.20
a. to determine the frequency, from the expression fr angular wave frequency we have
w=2πf hence
f=w/2π
if we substitute we arrive at
b. to determine the wave length, we use
c. the wave speed v is express as the product of the frequency and the wavelength. Hence