All categories

3 years ago

A cyclist rode at an average speed of 20 mph for 15 miles. How long was the ride?

Physics

1 answer:

Scrat [10]3 years ago

4 0

the answer is 45 minutes

You might be interested in

Svet_ta [14]

C. <span>If the temperature of water is increased, then it will change into steam is stating a hypothesis.</span>

6 0

3 years ago

Read 2 more answers

Which statement accurately describes impulse?<br> State corrrect ans

ser-zykov [4K]

Where are the statements at ?

5 0

4 years ago

You are driving up a long, inclined road. After 1.50 mi you notice that signs along the roadside indicate that your elevation ha

Alenkasestr [34]

Answer:

a. $3.98^{0}$

b. $1.91mi$

Explanation:

The data given are

Height,h=550ft,

length of incline plane, L=1.50 miles

first we convert all parameters to meters

since 1ft=0.3048m then 550ft will be 167.76m

also 1mile=1609.34m, hence 1.5mile will be 2414m

From the diagram attached, the length and height formed a simple triangle with the length being the hypotenuse and the height being the opposite.

Hence using SOHCAHTOA, we can conclude that the angle will be

$sin\alpha =\frac{h}{l}\\\alpha=sin^{-1}\frac{167.76}{2414}\\\alpha =3.98^{0}$

b. the new height becomes

$h=550+150=700ft\\h=0.3048*700=213.36m$

going by the same formula, we solve the new length s

$sin\alpha =\frac{213.36}{l}\\ l=\frac{213.36}{sin3.98}\\ l=3073.99m\\l=1.91mi$

5 0

3 years ago

Read 2 more answers

Zone between each team's blue line and goal line in ice hocky

Aleksandr [31]

Answer:Each goal line is 11 feet (3.4 m) from the end boards. NHL blue lines are 75 feet (22.9 m) from the end boards and 50 feet (15.2 m) apart.

Explanation:When the other team is on the attack, the defensive zone is the area between your goal line and your blue line. The central ice area between the two blue lines (neither the defending nor the attacking zone). When the your team is on the attack, the offensive zone is the area between blue line and your opponents goal.

3 0

3 years ago

Marcy pulls a backpack on wheels down the 100 m hall. The 60N force is applied at an angle of 30° above the horizontal. How much

shutvik [7]

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

6 0

3 years ago