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3 years ago

Can someone please help me with this question please ?

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

x=43

Step-by-step explanation:

Since the lines are parrallel, the angle underneath the one you are finding is equal to 65. To find the total value of (x+72) you subtract 65 from 180, giving you 115.

x+72 = 115

then you subtract 72 from both sides

x=43

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On a map the perimeter of the is 0.251 meters. The actual perimeters of the park is 1,000 times as large. What is the actual per

raketka [301]

The actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Further explanation:

Given:

The perimeter of the park is on a map $0.251{\text{ meters}}$ . The measured perimeter of the park is 1000 times as large.

Calculation:

The distance of the closed figure is called as the perimeter.

The perimeter of the attached Figure 1 can be calculated as,

$\begin{aligned}{\text{Perimeter}}&=a+a+b+b\\&=2\left({a+b}\right)\\\end{aligned}$

Here, $x,y{\text{ and }}z$ is the length of the shape.

From place value chart, 10 tens is equal to 1 hundreds.

Tenths are one place after the decimal and hundredths are two places after the decimal.

Two tenths can be written in the form of decimal as follows:

$\dfrac{2}{{10}}=0.2$

Five hundredths can be written in the form of decimal as follows:

$\dfrac{5}{{100}}=0.05$

One thousandths can be written in the form of decimal as follows:

$\dfrac{1}{{1000}}=0.001$

Therefore, the number 0.251 can be written as,

$\begin{aligned}0.251&=\frac{2}{{10}}+\frac{5}{{100}}+\frac{1}{{1000}}\\&=0.2+0.05+0.001\\&=0.251\\\end{aligned}$

On the map the perimeter of the park is $0.251{\text{ meters}}$ .

Let ${\text{P}}$ be the actual perimeter of the park.

The actual perimeter of the park can be calculated as follows,

$\begin{aligned}{\text{P}}&=0.251\times1000\\&=251{\text{ meters}}\\\end{aligned}$

Thus, the actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Learn more:

1. Learn more about problem on function brainly.com/question/1632445

2. Learn more about problem on triangle brainly.com/question/7437053

3. Learn more about problem on range and domain of functions brainly.com/question/3412497

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Numbers

Keywords: Perimeter, park, map, , measured, 1000 times large, distance, closed figure, length, shape, place value chart, hundreds, tenths.

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3 years ago

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The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?

MaRussiya [10]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}$

$~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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