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3 years ago

Round 6(2f-4)=31 i need help with this

Mathematics

1 answer:

bonufazy [111]3 years ago

4 0

Answer:

f ≈ 5

Step-by-step explanation:

Step 1: Write equation

6(2f - 4) = 31

Step 2: Solve for f

Distribute 6: 12f - 24 = 31

Add 24 on both sides: 12f = 55

Divide both sides by 12: f = 55/2

Simplify: f = 4.58333

Round: f ≈ 5

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Answer:

$85

Step-by-step explanation:

5000 x $70 = $350,000

4950 x $71 = $351,450

4900 x $72 = $352,800

etc.

Create an equation for the monthly revenue:

f(n) = (5000 - 50n) x (70 + n)

= 350000 + 5000n - 3500n - 50n²

= 350000 + 1500n - 50n²

where n is the amount the ticket price is increased from $70.

Differentiate, equal to zero and solve for n to find the value of n when the monthly revenue is at its maximum:

f'(n) = 1500 - 100n

1500 - 100n = 0

1500 = 100n

15 = n

Therefore, the maximum monthly revenue is when n = 15.

So the cost of the ticket will be 70 + n = 70 + 15 = 85

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2 years ago

-2/3- (-3/4) Simplify if needed Brainliest Also, 5/6+5/12

bazaltina [42]

Answer:

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

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Step-by-step explanation:

Given

$-\frac{2}{3} - (-\frac{3}{4})$

Required

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$-\frac{2}{3} - (-\frac{3}{4})$

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Take LCM

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Take LCM

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Answer:

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