Which of the following are solutions to the cubic equation x^3+4x^2+4x=0

Please help!

Reika [66]

Answer:

(1,-5)

Step-by-step explanation:

The given system of inequalities are;

$y\:$

and

$y\:$

The point that is a solution will satisfy the two inequalities.

Checking for (1,-5)

$-5\:$ and $-5\:$

$-5\:$ : True $-5\:$ : True

This point lies in the solution region.

Checking for (1,5)

$5\:$ and $5\:$

$5\:$ : False $5\:$ : False

This point does not lie in the solution region.

Checking for (5,1)

$1\:$ and $1\:$

$1\:$ : False $1\:$ : True

This point does not lie in the solution region.

Checking for (-1,5)

$5\:$ and $5\:$

$5\:$ : True $5\:$ : False

This point does not lie in the solution region.

4 0

3 years ago

Read 2 more answers

I really need help if anyone can help that would be great

Oliga [24]

Factor the denominator:

(3x-1)(x+2)

every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.

since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.

the answer here is C.

5 0

3 years ago

The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid

ryzh [129]

Given:

The bases of a trapezoid lie on the lines

$y=2x+7$

$y=2x-5$

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

On comparing $y=2x+7$ with slope intercept form, we get

$m_1=2,b_1=7$

On comparing $y=2x-5$ with slope intercept form, we get

$m_2=2,b_2=-5$

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

$m=m_1=m_2=2$

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

$b=\dfrac{b_1+b_2}{2}$

$b=\dfrac{7-5}{2}$

$b=\dfrac{2}{2}$

$b=1$

So, the y-intercept of the required line is 1.

Putting m=2 and b=1 in slope intercept form, we get

$y=2x+1$

Therefore, the equation of line that contains the midsegment of the trapezoid is $y=2x+1$ .

7 0

2 years ago

What is the verbal for x/2

tatiyna

X ( a number) / (divided by) 2 (two)

A number divided by 2.
or
The quotient of a number, x, and 2.

5 0

2 years ago

Solve for b. <br><br> 1/7= 90/91 +b

yanalaym [24]

♡ The Question ♡

・1/7 = 90/91 + B

Solve for B!

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

* ♡ The Answer ♡

・B = -11/13

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

・1/7 = 90/91 + B

Switch sides!

90/91 + B = 1/7

Subtract 90/91 from both sides!

90/91 + B - 90/91 = 1/7 - 90/91

Simplify!

90/91 + B - 90/91 : B

90/91 + B - 90/91

90/91 - 90/91 = 0

= B

Simplify!

1/7 - 90/91 : -11/13

1/7 - 90/91

= 13/91 - 90/91

Combine the fractions!

= 13 - 90 over 91

Subtract the numbers! : 13 - 90 = -77

= -77/91

Apply the fraction rule! : -a/b = -a/b

= -77/91

Cancel the common factor! : 7

= -11/13

B = -11/13

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

*♡ Tips ♡

・No tips provided!

3 0

3 years ago