Which of the following are solutions to the cubic equation x^3+4x^2+4x=0

Mathematics

1 answer:

viktelen [127]2 years ago

3 0

Answer:

337285

Step-by-step explanation:

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The average cost of driving a medium sedan in 2012 was 0.62 per mile. How much would it have cost to drive such a car 11,000 mil

azamat

Answer:

6,820 dollars

Step-by-step explanation:

multiple 0.62 times 11,000

8 0

2 years ago

The value of a truck after t years is represented by the function f(t)=22,200(0.92)t .

n200080 [17]

ANSWER:
The initial value of the truck is $22,200

EXPLANATION:
For the given function

f(t) = 22,200(0.92)^t

We know that at t = 0, we have

 f(0) = 22,200(0.92)^0 = 22,200

which is the value of the truck initially. So, the correct answer is

The initial value of the truck is $22,200

6 0

2 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

Slope:

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

Slope:

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$