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3 years ago

5

f(x) has domain , and range . A 2-column table with 5 rows. Column 1 is labeled x with entries negative 4, negative 2, 0, 2, 4.

Column 2 is labeled f (x) with entries negative 2, negative 1, 0, 1, 2.

1 answer:

laiz [17]3 years ago

5 0

Answer:

Domain: {-4, -2, 0, 2, 4}

Range: {-2, -1, 0 1, 2}

Step-by-step explanation:

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$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

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(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

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$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

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Sustituye:

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Podemos hacer que esto se vea un poco mejor:

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amid [387]

It is a relation but not a function

Step-by-step explanation:

Given

(3,6) (3,7) (-2,-5) (-9,11)

First of all we have to define both terms: Relation and Function

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A relation can be a function only if there is no repetition in domain i.e. no first element in each ordered pair should be repeated.

In the given set of ordered pairs, they are relation as all the ordered pairs have two values.

While the given relation is not a function, as there is repetition in first elements of two ordered pairs i.e. 3 is repeated in (3,6) (3,7)

Hence,

It is a relation but not a function

Keywords: Functions, Relations

Learn more about functions at:

#LearnwithBrainly

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