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boyakko [2]
3 years ago
13

PLEASE HELP

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

(x^4-2) (x^4 -1)


Discussion:


Let u = x^4, then

x^8 - 3x^4 + 2

= u^2 - 3u + 2

= (u -2) ( u -1)

= (x^4-2) (x^4 -1)



Thank you,

MrB

user100 [1]3 years ago
5 0

Answer:  (x - 1)(x + 1)(x² + 1)(x⁴ - 2)

<u>Step-by-step explanation:</u>

Given: x⁸ - 3x⁴ + 2

Let u = x⁴

then we get: u² - 3u + 2

Factor: (u - 1)(u - 2)

Substitute (replace u): (x⁴ - 1)(x⁴ - 2)    <em>repeat these steps for x⁴ - 1</em>  

***********************************************

x⁴ - 1

Let u = x²

then we get: u² - 1

Factor: (u - 1)(u + 1)

Substitute (replace u): (x² - 1)(x² + 1)   <em>       factor x² - 1</em>

<em>*</em>***********************************************

x² - 1

Factor: (x - 1)(x + 1)


Next, put all the factors together.  <em>You should have 8 x's (degree of 8)</em>

(x⁴ - 2)(x² + 1) (x - 1)(x + 1)

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Reika [66]

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5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

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We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

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x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

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Option (c) is correct.

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2 years ago
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