Answer:
a = 2 m/s2
Explanation:
we know from newtons 2nd law
F = ma.
we also know that from hookes law we have
F = kx
equate both value of force to get value of acceleration
kx = ma,
where,
k is spring constant = 8.0 N/m
x is maximum displacement 0.10 m
m is mass of object 0.40 kg
a = \frac{kx}{m}
= \frac{8 *0 .10}{0.40}
a = 2 m/s2
Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive
Answer:
18000 J
Explanation:
From the question given above, the following data were obtained:
At point 4:
Mass of cart = 600 Kg
Velocity of cart (v) = 7.745 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 600 × 7.745²
KE = 300 × 7.745²
KE ≈ 18000 J
Therefore, the mechanical energy of the cart at point 4 is 18000 J
The true answer is the choice <span>B.Anton van Leeuwenhoek
this one was a Dutch biologist, inventor and physicist (1632, 1723). he has discoverd the moving objects from pond water undr his microscope, the animalcules.</span>
This isn’t anything related to physics dude
