Ayudaaa dos puntos importantes sobre el reglamento de la marcha

The slow, steady downhill flow of loose, weathered Earth materials is called A. flow. B. slide. C. creep. D. slump.

Art [367]

I beileve its b
Hope this helps☺

7 0

3 years ago

Read 2 more answers

_ is the name given to the heat energy received from the sun

Travka [436]

Answer:

The think the answer is solar radiation.

Explanation:

here, we gain the heat from the sun through a radiation. When it travels from the sun the harmful radiation are absorbed by ozone layer and heat enegry is provided to the surface of the Earth.

hope it helps..

6 0

4 years ago

Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th

lozanna [386]

Answer:

Part a)

Velocity of sled

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

Velocity of sled

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

$0 = m_1(v - s) + (m_2 + M)v$

$v = \frac{m_1 s}{m_1 + m_2 + M}$

so velocity of the sled + other person is

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s$

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f$

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f$

Now we have

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s$

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

here we know all values of speed as we found it in part a) and part b)

4 0

3 years ago

PLEASE HELP GREATLY APPRECIATED IF YOU DO

Yuliya22 [10]

Answer:

a. 38400j

Explanation:

p= mgh

2400×10×1.6

3 0

3 years ago

The 2nd largest hailstone every measured fell in Aurora, Nebraska, in 2003. The circumference of that hailstone was 16 inches. U

8_murik_8 [283]

Answer:

1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?

2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?

3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?

Explanation:

1. If the circumference (L) of the stone is 16 inches, then from the following equation

$L = 2\pi R$

$R = \frac{L}{2\pi} = \frac{16}{2\pi} = 2.54 ~inches$

$D = 2R = 5.09 ft$

1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft

2. The total volume is

$V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (2.54)^3 = 68.64~in^3\\68.64 ~in^3 = 0.03~ft^3$

3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.

$V = 20*12.92 = 258.4~cm/s = 2.584~m/s$

2.584 m/s = 5.78 mph

4 0

3 years ago

Ayudaaa dos puntos importantes sobre el reglamento de la marcha ​

Ayudaaa dos puntos importantes sobre el reglamento de la marcha