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3 years ago

6

Tyler's favourite number is 8642, and he tries to fit it into everything he does. If he wishes to do that much work by climbing

stairs, how many stairs must he climb if each stair is an average of 18 cm tall and Tyler's mass is 64 kg?

1 answer:

Brums [2.3K]3 years ago

6 0

Answer:

2014

Explanation:

none

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A truck driver is broadcasting at a frequency of 27.075 MHz with a CB (citizen's band) radio. Determine the wavelength of the el

Sergio [31]

Answer:

11m

Explanation:

Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;

Wavelength ¶ = wave speed (v) /frequency (f)

Given the speed of light c = 2.9979 10^8 m/s.

frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz

Wavelength = 2.9979 10^8/27.075×10^6

Wavelength = 0.11×10^2

Wavelength = 11m

Therefore, the wavelength of the electromagnetic wave being used is 11m

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3 years ago

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3 years ago

Two identical positive charges are placed near each other. At the point halfway between the two chargesTwo identical positive ch

Nitella [24]

Answer:The electric field is zero and the potential is positive.

Explanation:

Two identical positive charges are separated by a certain distance and midway between charges two identical positive charges are placed near each other.

So the Electric field at midway is zero because the electric field due to both charges add up to give zero electric field.(because they point in opposite direction)

Potential is scalar quantity and charges are positive so they add up to give potential.

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3 years ago

video for A door 1 m wide, of mass 15 kg, is hinged at one side so that it can rotate without friction about a vertical axis. It

natka813 [3]

Answer:

$\omega_f = 0.4\ rad/s$

Explanation:

given,

width of door dimension = 1 m

mass of door = 15 Kg

mass of bullet = 10 g = 0.001 Kg

speed of bullet = 400 m/s

$I_{total} =I_{door} + I_{bullet}$

$I_{total} =\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2$

a) from conservation of angular momentum

$L_i = L_f$

$mv\dfrac{W}{2} = I_{total}\omega_f$

$mv\dfrac{W}{2}= (\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2)\omega_f$

$\omega_f= \dfrac{mv\dfrac{W}{2}}{\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2}$

$\omega_f= \dfrac{\dfrac{mv}{2}}{\dfrac{MW }{3}+(\dfrac{mW}{4})}$

$\omega_f= \dfrac{\dfrac{0.01\times 400}{2}}{\dfrac{15\times 1 }{3}+(\dfrac{0.01\times 1}{4})}$

$\omega_f = 0.4\ rad/s$

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3 years ago

Which type of hearing problem can be reduced which ordinary hearing aids

Paul [167]

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