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2 years ago

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Emily simplified this expression. Expression: (5−2)2+23×4 Step 1: (3)2+23×4 Step 2: 9+23×4 Step 3: 9+9×4 Step 4: 9+36 Step 5: 45

Emily made a mistake. Which step shows her first mistake? Step 1 Step 2 Step 3 Step 4

1 answer:

Shtirlitz [24]2 years ago

3 0

Answer:

Step 2 shows Emily's first mistake.

Step-by-step explanation:

3(2) = 6

But instead of this Emily wrote 3(2) = 9.

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PLESE HELP GEOMETERY

nalin [4]

In this problem, you must use SohCahToa which basically means:

Sin - opposite over hypotenuse

Cosine - adjacent over hypotenuse

Tangent - Opposite over hypotenuse

So in this picture we have 4 -which is on the opposite side of x - and a 5 -which is the hypotenuse of the triangle. This means we must use sin.

Using a calculator you put in:

$sin^{-1} (\frac{4}{5} )$

Your answer is 53.13 degrees

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2 years ago

Madelyn is in a hot air balloon that has just taken off and is floating above its launching point. Eddie is standing on the grou

Morgarella [4.7K]

Answer:

8.9 meters

Step-by-step explanation:

this seems like a problem where you can use the pythagorean theorem:

you know one of the two legs (6m) and the hypotenuse (9m), you must find the other leg

a^2 + 6^2 = 9^2

a^2 + 36 = 81

a^2 = 45

a = $\sqrt{45}$ or $\sqrt{9}$ · $\sqrt{5}$ which simplifies to be 3 $\sqrt{5}$ or approx. 8.9 meters

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2 years ago

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goldenfox [79]

Answer:

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Step-by-step explanation:

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2 years ago

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Simplify the expression 8(2x - 6y + 3) using the distributive property. *

yawa3891 [41]

Answer:

16x - 48y +24

Step-by-step explanation:

We can use the distributive property to expand:

8(2x - 6y + 3)
8 x 2x - 8 x 6y + 8 x 3
16x - 48y + 24

Hope this helps!!

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2 years ago

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If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

<u>Step 2: Differentiate</u>

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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2 years ago