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pantera1 [17]
3 years ago
9

Let f (x)sinx cosx, then f'(x) =A. Cos2xB. sin2xC. tan 2xD. cos2x - sin2x​

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

A. Cos2x

Step-by-step explanation:

f(x) = sin(x)cos(x) = (1/2) sin(2x)   using double angle formula.

f'(x) = ( (1/2)sin(2x) )' = 2(1/2)cos(2x) = cos(2x)

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