3

I will give brainlest for the right answer. Please don't just make up a random thing. PLEASE!

Alexxx [7]

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$30( \frac{1}{2} x - 2) + 40( \frac{3}{4} y - 4) = \\$

$(30 \times \frac{1}{2} x) -( 30 \times 2 )+ (40 \times \frac{3}{4} y )- (40 \times 4 )= \\$

$15x - 60 + 30y - 160 = \\$

$15x + 30y - 220$

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The correct answer is Option Three .

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6 0

2 years ago

Read 2 more answers

Find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches.

Nataly_w [17]

Surface area of a ball:
S=4πr^2=4*π*5^2=100π

Volume of a circle:
V=4/3*π*r^3=4/3*π*125=(500/3)*π=165π

The approximate surface-area-to-volume ratio would be 1:1,5

6 0

3 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$