Answer:
0.1527
Step-by-step explanation:
Given that a researcher wishes to conduct a study of the color preferences of new car buyers.
Suppose that 50% of this population prefers the color red
15 buyers are randomly selected
Let X be the no of buyers who prefer red.
X has exactly two outcomes red or non red.
Also each buyer is independent of the other
Hence X is binomial with p = 0.5 and n = 15
Required prob =The probability that exactly three-fifths of the buyers would prefer red
= P(X=9)
= 
=
+1/31 and -1/31
Hope this helps.
12 flips, 11 heads, 1 tails
Let's say there's a 50-50 chance of landing heads.
There are 12 flips and 12 specific outcomes.
The probability is 2^(-12) = 1/4096 = 0.0244%
If the last flip doesn't matter, then the probability would be 2^(-11) = 1/2048 = 0.0488%.
Have an awesome day! :)
From your friendly Helper-in-Training, collinjun0827
Answer:
the width is 10 m
Step-by-step explanation:
if the relationship between area and width is
A = 80*w − w²
for an area A=700 m² , we have
700 m² = 80*w − w²
w² - 80*w + 700 m² = 0
aw² + b*w + c = 0
where a=1 , b=-80 and c=700
this quadratic equation has as solution the following formula
w = [-b ± √ ( b² - 4*a*c) ]/(2*a)
replacing values
w = [80 ± √ ( 80² - 4*1*700) ]/(2*1) = (80 ± 60)/2
then
w₁=(80 - 60)/2 = 10 m
w₂ =(80 + 60)/2 = 70 m
since the area has the form A= length * width = 80*w − w² = (80− w)*w
then the length of the rectangle is
length = 80− w
for w₁=10 m → length = 80− 10 = 70 m
for w₁=70 m → length = 80− 70 = 10 m
by definition the shorter side is the width ( and the longer one , the length) , therefore the only possible option is the first one .
Thus the width is 10 m
Use Photomath it works well
