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3 years ago

What are the degree and leading coefficient of the polynomial? - 2u + 12u ^ 2 + 8 - u ^ 9

Mathematics

1 answer:

USPshnik [31]3 years ago

7 0

Answer:

Step-by-step explanation:

hello :

- 2u + 12u ² + 8 - u ^ 9 = -1u ^ 9+12u² -2u+8...standard form

the degree is 9 and leading coefficient is -1

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Rewrite the equation below so that it does not have fractions.

bearhunter [10]

Answer:

$60+10x=6$

Step-by-step explanation:

Hi there!

$4+\displaystyle \frac{2}{3} x=\frac{2}{5}$

To get rid of the fraction $\displaystyle \frac{2}{3}$ , multiply both sides of the equation by 3 (the denominator):

$3(4+\displaystyle \frac{2}{3} x)=3(\frac{2}{5})\\\\3*4+\frac{3*2}{3}x =\frac{3*2}{5} \\\\12+2x =\frac{6}{5}$

To get rid of the fraction $\displaystyle \frac{6}{5}$ , multiply both sides of the equation by 5 (the denominator):

$\displaystyle 5(12+2x) =5(\frac{6}{5})\\\\5*12+5*2x=\frac{5*6}{5} \\\\60+10x=6$

I hope this helps!

8 0

3 years ago

Read 2 more answers

The curve

kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x - 3}$

$\displaystyle y' = \frac{1}{2}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = (x - 3)^{\frac{1}{2}}$
Chain Rule: $\displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)$
Simplify: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1$
Multiply: $\displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x - 3}}$

Step 3: Solve

Find coordinates

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle 1 = \frac{1}{\sqrt{x - 3}}$
[Multiplication Property of Equality] Multiply √(x - 3) on both sides: $\displaystyle \sqrt{x - 3} = 1$
[Equality Property] Square both sides: $\displaystyle x - 3 = 1$
[Addition Property of Equality] Add 3 on both sides: $\displaystyle x = 4$

y-coordinate

Substitute in x [Function]: $\displaystyle y = \sqrt{4 - 3}$
[√Radical] Subtract: $\displaystyle y = \sqrt{1}$
[√Radical] Evaluate: $\displaystyle y = 1$

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0

3 years ago

Which of the following statements does not describe the structure of an atom?

blagie [28]

Answer:

B) Inside the nucleus of an atom are protons and electrons.

Explanation:

Inside the nucleus of an atom are protons and neutrons. Electrons orbit (kind of?) away from the nucleus.

8 0

2 years ago

Could someone help me with this im so confused

Arlecino [84]

Ok so basically the number by the X is your slope (m) and the other number is your y-intercept (b) so for example the first question your slope (m) 2/3 and your y-intercept (b) -2

6 0

3 years ago

Help me pls the questions are here

andreyandreev [35.5K]

3x + 7 = -x - 1
3x + 7 + = -1
4x + 7 = -1
4x = -1 - 7
4x = -8
x = -2

1 - 2x + 5 = 4x - 3
-2x + 6 = 4x - 3
6 = 4x - 3 + 2x
6 = 6x - 3
6 + 3 = 6x
9 = 6x
x = 6/9
x = 2/3

i helped you with the first two questions so you can see how you can solve it.

hope this helps, God bless!

6 0

3 years ago