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vichka [17]
2 years ago
14

In AABC, MZA = 16°, mZB = 49°, and a = 4. Find c to the nearest tenth.

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

  (c)  13.2

Step-by-step explanation:

The sum of angles in a triangle is 180°, so angle C is ...

  C = 180° -A -B

  C = 180° -16° -49° = 115°

The measure of side c can be found from the Law of Sines:

  c/sin(C) = a/sin(A)

  c = a·sin(C)/sin(A) = 4·sin(115°)/sin(16°)

  c ≈ 13.2

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3 years ago
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vlada-n [284]

Answer:

  x = 4

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the remote interior angles.

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  x = 4 . . . . . . divide by 10

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<em>Additional comment</em>

The exterior angle is (18)(4) +5 = 77°. The marked unknown interior angle is -1+(8)(4) = 31°. The sum of the two remote interior angles is 46°+31° = 77°. The unmarked interior angle is 180°-77° = 103°.

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2 years ago
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Step-by-step explanation:

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3 years ago
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What is the sum of the following infinite series?<br> 5+ 15/7 + 45/49 + 135/343
liberstina [14]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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