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vichka [17]
2 years ago
14

In AABC, MZA = 16°, mZB = 49°, and a = 4. Find c to the nearest tenth.

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

  (c)  13.2

Step-by-step explanation:

The sum of angles in a triangle is 180°, so angle C is ...

  C = 180° -A -B

  C = 180° -16° -49° = 115°

The measure of side c can be found from the Law of Sines:

  c/sin(C) = a/sin(A)

  c = a·sin(C)/sin(A) = 4·sin(115°)/sin(16°)

  c ≈ 13.2

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3 years ago
Sabiendo que el segmento DE es paralelo a la base del triángulo, las medidas de los segmentos a y b son...
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Answer:

Para resolver correctamente el ejercicio debemos seguir los pasos que se muestran en la explicación.

Step-by-step explanation:

El ejercicio enunciado de manera completa es el siguiente:

7.Sabiendo que el segmento DE es paralelo a la base del triángulo, las medidas de los segmentos a y b son:  

(la gráfica del ejercicio se guardo como archivo adjunto)

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-Ninguna de las respuestas anteriores es correcta.

<em>SOLUCIÓN:</em>

<em>Pasos:</em>

-Primero debemos hallar el valor de a, la gráfica nos indica que debemos hacer,tenemos que restar 15 de 6; entonces:

a= 15cm -6cm=9 cm

-Ahora debemos aplicar el teorema de thales  ;como los segmentos son proporcionales podemos establecer la siguiente relación de esa manera podemos hallar el valor del segmento b;

   \frac{9}{b}=\frac{6}{7} ( para resolver debemos multiplicar en cruz)

 (9x7)=6xb

 63=6b (aquí debemos hallar el valor de b,para eso b pasa a dividir a 63)

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b= 10.5 cm

La respuesta correcta es:   a= 9cm y b= 10.5 cm

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