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3 years ago

2 -2y - 7+ 5y = 13 - 2y Is there one solution no solution or infinite solutions?

Mathematics

1 answer:

Oksanka [162]3 years ago

3 0

Answer:

one solution;y=-4

Step-by-step explanation:

-2y-7+-5y=13-2y

-7y-7=13-2y

-5y-7=13

-5y=20

y=-4

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3 years ago

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Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

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3 years ago

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Salsk061 [2.6K]

Answer:

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2 years ago

Find the area of the rhombus.

Stolb23 [73]

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3 years ago

Indicate a general rule for the nth term of this sequence. -6b, -3b, 0b, 3b, 6b. . .

SOVA2 [1]

The general rule for the nth term of the sequence is $a(n)=-6b+(n-1)(3b)$

Explanation:

The sequence is -6b, -3b, 0b, 3b, 6b, .....

To find the nth term of the sequence, we need to find the common difference and the first term of the sequence.

First term of the sequence = -6b

Common difference = $-3b-(-6b)=-3b+6b=3b$

Using this the nth term of the sequence can be determined.

Since, this is an arithmetic sequence, the general form of AP is given by the formula,

$a(n)=a+(n-1)d$

where a denotes the first term of the sequence and d denotes the common difference. Thus, $a=-6b$ and $d=3b$

Substituting the values in the general formula, we get,

$a(n)=-6b+(n-1)(3b)$

Thus, the general rule for the nth term of the sequence is $a(n)=-6b+(n-1)(3b)$

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3 years ago