Answer:
f=-1380N
Explanation:
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds
.the concluding part to the question should be
What is the impact force (impulse) on the board?
solution
from the Newton's second law of motion which states that
the rate of change in momentum is directly proportional to the force applied
f=m(v-u)/t
f=0.3(0-23.3)/0.005
f=-1380N
f=force impact
m=mass of the karates master's hand
t=time for the impact
v=0m/s final velocity
u=initial velocity
Aha! This is a fun question, likely AP Physics 1 if I'm not mistaken. This is how you solve it, you need the following equation.
Now on this question you don't need to actually use the mass and diameter of the earth as we are only
looking at the
factor of how much your weight would change, so you can just plug in some random numbers for the mass and radius. In my case I will use the original radius as being
2 meters and the original mass of the earth as being
20kg. You can actually just omit the mass of your body and the gravitational constant isn't necessary to be multiplied by because they will remain the same in both scenarios.
Original weight:
So the original weight in this circumstance is 5N. Now then if we double the mass to
40kg and the radius to
4m you will have the following.
So the original weight was 5N and after doubling the mass and radius the weight reduced to 2.5N. This means the factor which your weight would change by is .5 or decrease by 1/2.
I hope this helps you :) You can ask me if you have any additional physics questions.
I believe the first one is true because a transverse wave generally looks like a right angle. The second one is also true. May I ask what Physics class you are taking, regular, honors, AP Physics 1, AP Physics 2? Also how close are you to finishing it?
Answer:
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed= 16.7 kJ = 16700 J (1kJ=1000J)
m= mass of benzene = 225 g
c = specific heat capacity = 1.74 J/gK
Initial temperature of the water = = 20.0°C = 293 k
Final temperature of the water = = ?
Change in temperature ,
Putting in the values, we get:
The final temperature will be